Exponential distribution calculator

The exponential distribution describes waiting times between random events that happen at a constant average rate: calls to a help desk, arrivals at a counter, the lifetime of a part that does not wear. Enter the rate λ or the mean 1/λ and a value x to get the probabilities, the density and the quantile you need.

A positive number, for example 0.5 events per minute or a mean of 2 minutes.
A waiting time, 0 or more, in the same unit as the rate.
Optional: gives the probability of a value between x and x₂.
Optional, between 0 and 1: 0.9 gives the time below which 90 % of waits fall.
P(X ≤ x)0.7769
P(X > x)
0.2231
Density f(x)
0.111565
Quantile (value with that probability below it)
4.60517
Rate λ
0.5
Mean 1/λ
2
Median ln 2/λ
1.38629
Variance 1/λ²
4
Standard deviation 1/λ
2

Runs in your browser: nothing you enter is sent anywhere.

How to use it

  1. Choose whether you know the rate λ or the mean waiting time μ, and enter it.
  2. Enter x to get P(X ≤ x), P(X > x) and the density.
  3. Optionally add x₂ for the probability between two values, and a probability p for the quantile.

Formulas

For X ~ Exp(λ), x ≥ 0:

  • P(X ≤ x) = 1 − e^(−λx), P(X > x) = e^(−λx)
  • P(x₁ < X ≤ x₂) = e^(−λx₁) − e^(−λx₂)
  • f(x) = λe^(−λx)
  • Quantile x_p = −ln(1 − p)/λ; median ln 2/λ; mean 1/λ; variance 1/λ²

Worked example

Customers arrive at 0.5 per minute (mean gap 2 minutes). The chance that the next one arrives within 3 minutes is 1 − e^(−1.5) = 0.7769, so 0.2231 that you wait longer. The chance of a gap between 3 and 5 minutes is e^(−1.5) − e^(−2.5) = 0.141. Half of all gaps are shorter than the median 1.38629 minutes, and 90 % are shorter than 4.60517 minutes.

Tips and common mistakes

  • Keep units consistent: a rate per hour needs x in hours.
  • The rate and the mean are reciprocals; entering a mean of 2 as a rate of 2 gives very different answers.
  • The model assumes a constant rate; parts that wear out or queues with rush hours need other distributions.

Frequently asked questions

What are the formulas of the exponential distribution?

With rate λ: density f(x) = λe^(−λx), cumulative P(X ≤ x) = 1 − e^(−λx), survival P(X > x) = e^(−λx), for x ≥ 0. The mean and standard deviation are both 1/λ and the median is ln 2/λ.

What is the memoryless property?

P(X > s + t | X > s) = P(X > t): having already waited s minutes does not change the chance of waiting t more. The exponential is the only continuous distribution with this property.

How does it relate to the Poisson distribution?

If events occur as a Poisson process with λ events per unit of time, the time between consecutive events is exponential with rate λ, and the number of events in a unit of time is Poisson with mean λ.

How do I find the time by which 90 % of cases are done?

Use the quantile: x = −ln(1 − p)/λ. With λ = 0.5 per minute and p = 0.9 it is −ln(0.1)/0.5 = 4.60517 minutes.

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All tools in this category: Math ·Updated November 4, 2026

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