Bohr model calculator

Enter the nuclear charge Z (1 for hydrogen) and the levels the electron jumps between. The calculator gives the wavelength and energy of the photon by the Rydberg formula, whether it is emitted or absorbed and which series it belongs to, and the energy, radius and speed of the electron on the starting level.

Photon wavelength656.112 nm
Wavelength with the proton's mass (hydrogen)
656.47 nm
Transition
Emission – a photon is given off
Series
Balmer (n = 2, visible and near UV)
Photon energy
1.8897 eV
Frequency
456.92 THz
Energy of the starting level
-1.5117 eV
Energy of the final level
-3.4014 eV
Ionization energy from the starting level
1.5117 eV
Orbit radius on the starting level
476.26 pm
Electron speed on the starting level
729.2 km/s

Runs in your browser: nothing you enter is sent anywhere.

How to use it

  1. Enter Z: 1 for hydrogen, 2 for He⁺, 3 for Li²⁺ – any atom stripped to one electron.
  2. Enter the starting and final levels. Falling to a lower level emits a photon; rising absorbs one.
  3. Read the photon wavelength, energy and frequency, the series, and the electron’s energy, radius and speed on the starting level.

Formulas

  • Level energy: Eₙ = −13.605693 eV × Z² ÷ n²
  • Orbit radius: rₙ = a₀ n² ÷ Z, a₀ = 52.9177 pm
  • Electron speed: vₙ = α c Z ÷ n, α ≈ 1/137.036
  • Rydberg formula: 1/λ = R∞ Z² (1/n₁² − 1/n₂²), R∞ = 10,973,731.568 1/m
  • Photon energy: E = E_upper − E_lower = h c ÷ λ

Worked example

Hydrogen, electron falls from n = 3 to n = 2:

  • 1/λ = 10,973,731.568 × (1/4 − 1/9) = 10,973,731.568 × 5/36 → λ = 656.112 nm (656.47 nm with the proton’s mass), emission, Balmer series
  • E = 13.605693 × 5/36 = 1.8897 eV, frequency 456.92 THz
  • On n = 3: E₃ = −1.5117 eV, r₃ = 9 × 52.9177 = 476.26 pm, v₃ = 729.2 km/s

He⁺ (Z = 2) from n = 2 to n = 1: λ = 121.502 ÷ 4 = 30.376 nm, 40.8171 eV.

Tips

  • Levels are negative because the electron is bound; 0 eV means free. The ionization energy is the size of the level energy.
  • Lyman lines are ultraviolet, Balmer lines include the visible ones, Paschen and higher are infrared.
  • Vacuum wavelengths. Tables measured in air list slightly shorter values, for H-alpha 656.28 nm.

Frequently asked questions

What are the energy levels of hydrogen?

Eₙ = −13.6057 eV ÷ n² in the Bohr model – −13.6057 eV for n = 1, −3.4014 eV for n = 2, −1.5117 eV for n = 3. For an ion with nuclear charge Z multiply by Z².

What is the Rydberg formula?

1/λ = R∞ × Z² × (1/n₁² − 1/n₂²), R∞ = 10,973,731.568 1/m. For hydrogen 3 → 2 it gives 656.112 nm, the red H-alpha line of the Balmer series.

Why are there two wavelengths for hydrogen?

The plain formula assumes an infinitely heavy nucleus. A real proton moves a little too, which replaces R∞ by R_H = R∞ ÷ (1 + mₑ/mₚ) and makes the line 656.47 nm. That correction is shown for Z = 1.

How far is the Bohr model right?

For one-electron atoms its energy levels match experiment closely and it explains the hydrogen spectrum. It fails for atoms with several electrons and for fine details of the lines, which need quantum mechanics.

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All tools in this category: Math ·Updated November 6, 2026

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