pH calculator

Choose the quantity you know, type its value and read the other three. Concentrations are in mol/L and accept scientific notation such as 2.5e-4. All results assume water at 25 °C, where the ion product Kw is 1e-14.

Concentrations can use scientific notation, such as 1e-7 or 2.5e-4. Valid at 25 °C only.
pOH11
[H⁺]0.001 mol/L
[OH⁻]1.000e-11 mol/L
pH
3
Solution at 25 °C
Acidic (pH below 7)

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How to use it

  1. Select which quantity you know: pH, pOH, [H⁺] or [OH⁻].
  2. Type its value. Use scientific notation for tiny concentrations.
  3. Read the other three values and whether the solution is acidic, neutral or basic.

How it works

With Kw = 1e-14 at 25 °C: pH = −log₁₀[H⁺], pOH = 14 − pH, [H⁺] = 10^(−pH) and [OH⁻] = 10^(−pOH). Below 7 the solution is acidic and above 7 it is basic.

Worked example

[H⁺] = 2.5e-4 mol/L gives pH = −log₁₀(2.5e-4) = 4 − 0.398 = 3.602 and pOH = 14 − 3.602 = 10.398, so [OH⁻] = 4.0e-11 mol/L. pH 3 gives [H⁺] = 0.001 mol/L and pOH 11.

Tips

  • Each pH unit is a factor of ten in [H⁺]: pH 3 is ten times more acidic than pH 4.
  • Report pH with as many decimals as you have significant digits in the concentration.

Frequently asked questions

What is the pH formula?

pH = −log₁₀[H⁺], where [H⁺] is the hydrogen ion concentration in mol/L. In the same way pOH = −log₁₀[OH⁻]. A solution with [H⁺] = 1e-3 mol/L has pH 3.

How are pH and pOH related?

At 25 °C, pH + pOH = 14, because the product [H⁺] × [OH⁻] equals Kw = 1e-14. The relation changes with temperature, because Kw does, so this tool applies only near 25 °C.

Can pH be below 0 or above 14?

Yes. Concentrated strong acids and bases can give values outside 0 to 14. The calculator accepts them, but for very concentrated solutions the real pH differs from the ideal formula because activities differ from concentrations.

How do I find pH of a weak acid?

First find the equilibrium [H⁺] from the acid's Ka and concentration, then enter that [H⁺] here. This tool converts between the four quantities and does not solve equilibrium problems.

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