Log reduction calculator

Enter the microbial count before and after a treatment to get the log reduction and the percent killed. Or convert a claim such as “4-log” or “99.99 %” into the other form and see how many organisms out of a starting population would survive.

Start from
Log reduction5
Percent reduction
99.999 %
Survivors left
10
Organisms killed
999,990
Surviving fraction
0.00001
One survivor in
100,000

Runs in your browser: nothing you enter is sent anywhere.

How to use it

  1. Choose what you know: counts before and after, a log reduction, or a percentage.
  2. Enter the values. With a log or percentage, the count before treatment shows how many organisms would survive (enter 0 to leave it out).
  3. Read the log reduction, the percent reduction, the survivors and the surviving fraction.

Formulas

  • Log reduction = log₁₀(N₀ ÷ N)
  • Percent reduction = (1 − N ÷ N₀) × 100 = (1 − 10^(−log)) × 100
  • Log from percent = −log₁₀(1 − percent ÷ 100)
Log reduction Percent Survivors of 1,000,000
1 90 % 100,000
2 99 % 10,000
3 99.9 % 1,000
4 99.99 % 100
5 99.999 % 10
6 99.9999 % 1

Worked example

A disinfectant test starts with 1,000,000 CFU and recovers 10 CFU: log₁₀(1,000,000 ÷ 10) = log₁₀(100,000) = 5-log, which is 99.999 %. One organism in 100,000 survived.

From 5 × 10⁷ to 2,500: log₁₀(20,000) = 4.301, a 99.995 % reduction.

Tips

  • Use the same units before and after. CFU/mL with CFU/mL, CFU per surface with CFU per surface.
  • Logs add up. Two treatments of 2 log and 3 log in sequence give 5 log — percentages do not add that simply.
  • Watch rounding in claims. “99.9 %” is only 3 log; the difference between 99.9 % and 99.999 % is a hundredfold.

Frequently asked questions

What is a log reduction?

The base-10 logarithm of how many times the number of live organisms went down: log reduction = log₁₀(N₀ ÷ N). A 1-log reduction leaves a tenth, 2-log a hundredth, 5-log one in 100,000.

How do I convert log reduction to percent?

Percent reduction = (1 − 10^(−log)) × 100. So 1 log = 90 %, 2 log = 99 %, 3 log = 99.9 %, 4 log = 99.99 % and 5 log = 99.999 %. Back the other way: log = −log₁₀(1 − percent ÷ 100).

Is 99.9 % killed good enough?

It depends on how many there were. 99.9 % of a million bacteria still leaves 1,000 alive. That is why disinfection and sterilisation are specified in logs: sterilisation processes are commonly designed for far higher reductions than disinfectants.

What if no organisms are recovered after treatment?

A count of 0 gives an infinite logarithm, so it is reported as “greater than” the log of the starting count divided by the detection limit. Enter the detection limit (for example 1 or 10) as the count after treatment and read the result as a minimum.

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