Motor current calculator (full-load amps)

Enter the rated output power of the motor in kW or hp, the supply voltage, the efficiency and the power factor from the nameplate. The calculator gives the line current at full load, the electrical input power and the apparent power.

Supply
Power unit
V
%
Full-load current14.15 A
Electrical input power
8.333 kW
Apparent power
9.804 kVA
Rated power in hp
10.06 hp

Runs in your browser: nothing you enter is sent anywhere.

How to use it

  1. Choose the supply: DC, single phase or three phase.
  2. Enter the rated output power and pick kW or hp.
  3. Enter the voltage (line-to-line for three phase), the efficiency in % and, for AC, the power factor.
  4. Read the full-load current, the electrical input power and, for AC, the apparent power in kVA.

Formulas

With rated output P (W), efficiency η and power factor cos φ:

  • Input power: P_in = P / η.
  • DC: I = P_in / V.
  • Single phase: I = P_in / (V × cos φ).
  • Three phase: I = P_in / (√3 × V × cos φ).
  • Apparent power (AC): S = P_in / cos φ.

1 hp = 745.7 W (mechanical horsepower).

Worked examples

7.5 kW, 400 V three phase, η 90 %, cos φ 0.85: P_in = 7,500 ÷ 0.9 = 8,333 W; I = 8,333 ÷ (1.7321 × 400 × 0.85) = 14.15 A; S = 8.333 ÷ 0.85 = 9.804 kVA. The motor is 10.06 hp.

1 hp, 230 V single phase, η 75 %, cos φ 0.8: P_in = 745.7 ÷ 0.75 = 994.3 W; I = 994.3 ÷ (230 × 0.8) = 5.4 A.

1 kW DC motor at 24 V, η 85 %: P_in = 1,176 W; I = 1,176.5 ÷ 24 = 49.02 A.

Tips

  • Part load changes everything. Below full load both efficiency and power factor fall, so current does not drop in proportion to the load.
  • Star or delta? Use the line voltage the motor is connected to: a 230/400 V motor in delta on a 230 V line draws √3 times the current it draws in star on 400 V.
  • Variable-speed drives draw input current set by the drive’s own power factor, not the motor’s.

Frequently asked questions

How do I calculate three-phase motor current?

I = P / (√3 × V × η × cos φ), with P the rated output in watts and V the line-to-line voltage. A 7.5 kW motor on 400 V with 90 % efficiency and cos φ 0.85 draws 7,500 ÷ (1.732 × 400 × 0.9 × 0.85) = 14.15 A.

Why divide by efficiency?

The nameplate power of a motor is the mechanical power at the shaft. The supply must also cover the losses, so the electrical input is P / η, and the current follows from that input power.

Is the calculated current the same as the nameplate current?

It should be close when you use the nameplate efficiency and power factor. Nameplate current is measured and rounded, so expect small differences. For cable and protection sizing follow the nameplate and your local wiring rules.

What about starting current?

This is the running current at full load. A motor started direct on line draws several times more for a short time; the exact multiple is given by the manufacturer (locked-rotor current or code letter).

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